What is the order of stability of 1^{circ}, 2 | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The stability of carbocations is primarily determined by the inductive effect and hyperconjugation. $3^{\circ}$ carbocations are the most stable d

Vedclass · Accepted Answer

$3^{\circ} > 2^{\circ} > 1^{\circ} > \overset{\oplus}{C}H_3$

Vedclass · Answer

(D) The stability of carbocations is primarily determined by the inductive effect and hyperconjugation. $3^{\circ}$ carbocations are the most stable due to the maximum number of alkyl groups providing electron density through the $+I$ effect and hyperconjugation. $2^{\circ}$ carbocations are less stable than $3^{\circ}$ but more stable than $1^{\circ}$. $1^{\circ}$ carbocations are less stable than $2^{\circ}$. $\overset{\oplus}{C}H_3$ (methyl carbocation) is the least stable as it lacks any alkyl groups to stabilize the positive charge. Therefore,the correct order of stability is $3^{\circ} > 2^{\circ} > 1^{\circ} > \overset{\oplus}{C}H_3$.

What is the order of stability of $1^{\circ}, 2^{\circ}, 3^{\circ},$ and $\overset{\oplus}{C}H_3$ carbocations?

Similar Questions

Arrange the following cations in decreasing order of their stability:
$(a)$ $CH_3^+$
$(b)$ $F-CH_2-CH_2^+$
$(c)$ $Br-CH_2-CH_2^+$
$(d)$ $CH_3-CH_2-CH_2^+$

Due to the presence of an unpaired electron,free radicals are .........

In which pairs,the first ion is more stable than the second?

Classify the following species into carbocation,free radical,and carbanion:
$CH_3^{\bullet}, CH_3^{+}, \bar{C}H_3, (CH_3)_3C^{\bullet}, (CH_3)_3C^{+}, (CH_3)_2CH^{+}, (CH_3)_3\bar{C}:, (CH_3)_3\ddot{C}H, C_6H_5CH_2^{\bullet}, CH_3\ddot{C}H_2, C_6H_5CH_2^{+}, CH_2=CHCH_2^{\bullet}, CH_2=CHCH_2^{+}$

The compound shown below undergoes racemization on reaction with aqueous acid. Which of the following structures best represents the intermediate responsible for this process?

Vedclass Test Series

Exam Paper Generator

Online Exam Module