What is the coefficient of mutual inductance | vedclass

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(A) The formula for magnetic flux linkage in mutual induction is given by $\Delta \phi = M \Delta I$,where $\Delta \phi$ is the change in magnetic flu

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$2$

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(A) The formula for magnetic flux linkage in mutual induction is given by $\Delta \phi = M \Delta I$,where $\Delta \phi$ is the change in magnetic flux,$M$ is the coefficient of mutual inductance,and $\Delta I$ is the change in current.Given:$\Delta \phi = 2 	imes 10^{-2} \, Wb$$\Delta I = 0.01 \, A = 10^{-2} \, A$Substituting the values into the formula:$2 	imes 10^{-2} = M 	imes 10^{-2}$$M = \frac{2 	imes 10^{-2}}{10^{-2}}$$M = 2 \, H$Therefore,the coefficient of mutual inductance is $2 \, H$.

What is the coefficient of mutual inductance when the magnetic flux changes by $2 \times 10^{-2} \, Wb$ and the change in current is $0.01 \, A$?

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