What is the change in oxidation number of Cr | vedclass

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(D) In the given reaction,we need to find the change in the oxidation number of $Cr$ from the reactant side to the product side.In the dichromate ion,

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$+6$ to $+3$

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(D) In the given reaction,we need to find the change in the oxidation number of $Cr$ from the reactant side to the product side.In the dichromate ion,$Cr_2O_7^{2-}$,let the oxidation number of $Cr$ be $x$.$2x + 7(-2) = -2$$2x - 14 = -2$$2x = 12$$x = +6$In the product,the chromium ion is $Cr^{3+}$,so the oxidation number of $Cr$ is $+3$.Therefore,the oxidation number of $Cr$ changes from $+6$ to $+3$.

What is the change in oxidation number of $Cr$ in the following redox reaction?
$3H_2O_2(aq) + Cr_2O_7^{2-}(aq) + 8H^+(aq) \rightarrow 3O_2(g) + 2Cr^{3+}(aq) + 7H_2O(l)$

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What is the change in oxidation number of $Cr$ in the following redox reaction?$3H_2O_2(aq) + Cr_2O_7^{2-}(aq) + 8H^+(aq) \rightarrow 3O_2(g) + 2Cr^{3+}(aq) + 7H_2O(l)$