The oxidation numbers of the two Cl atoms in | vedclass

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(B) Bleaching powder is represented as $Ca(OCl)Cl$. In this compound,the calcium ion is $Ca^{2+}$. The two chlorine atoms are present in different env

Vedclass · Accepted Answer

$+1, -1$

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(B) Bleaching powder is represented as $Ca(OCl)Cl$. In this compound,the calcium ion is $Ca^{2+}$. The two chlorine atoms are present in different environments: $1$. One $Cl$ atom is part of the hypochlorite ion $(OCl^-)$,where the oxidation state of $O$ is $-2$,so $x + (-2) = -1$,which gives $x = +1$. $2$. The other $Cl$ atom exists as a chloride ion $(Cl^-)$,which has an oxidation state of $-1$. Therefore,the oxidation numbers of the two $Cl$ atoms are $+1$ and $-1$.

Column-$I$	Column-$II$
$A$. $Cr_2O_7^{2-}$	$1$. $+3$
$B$. $MnO_4^{-}$	$2$. $+4$
$C$. $VO_3^{-}$	$3$. $+5$
$D$. $FeF_6^{3-}$	$4$. $+6$
	$5$. $+7$

The oxidation numbers of the two $Cl$ atoms in bleaching powder,$CaOCl_2$,are

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Column-$I$ Column-$II$

$A$. $Cr_2O_7^{2-}$ $1$. $+3$

$B$. $MnO_4^{-}$ $2$. $+4$

$C$. $VO_3^{-}$ $3$. $+5$

$D$. $FeF_6^{3-}$ $4$. $+6$

$5$. $+7$

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