What is the probability that a non-leap year | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) non-leap year consists of $365$ days.Dividing $365$ by $7$,we get $52$ weeks and $1$ extra day.This extra day can be any one of the following: {Su

Vedclass · Accepted Answer

$\frac{1}{7}$

Vedclass · Answer

(C) non-leap year consists of $365$ days.Dividing $365$ by $7$,we get $52$ weeks and $1$ extra day.This extra day can be any one of the following: {Sunday,Monday,Tuesday,Wednesday,Thursday,Friday,Saturday}.Thus,the total number of outcomes is $n(S) = 7$.For the year to have $53$ Wednesdays,the extra day must be a Wednesday.There is only $1$ favorable outcome,which is {Wednesday}.Thus,$n(E) = 1$.The probability $P(E) = \frac{n(E)}{n(S)} = \frac{1}{7}$.

What is the probability that a non-leap year has $53$ Wednesdays?

Similar Questions

There are $10$ pairs of shoes in a cupboard from which $4$ shoes are picked at random. The probability that there is at least one pair is

The probability of getting $4$ heads in $8$ throws of a coin is:

From a group of $7$ men and $4$ ladies,a committee of $6$ persons is formed. What is the probability that the committee contains exactly $2$ ladies?

$A$ number is chosen at random from the first ten natural numbers. The probability that the number is odd and a perfect square is

When two dice are thrown,what is the probability that the sum of the numbers appearing on them is an even number?

Vedclass Test Series

Exam Paper Generator

Online Exam Module