What is the value of the effective atomic num | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The formula for the effective atomic number $(EAN)$ is given by: $EAN = Z - 	ext{oxidation state} + 	ext{number of electrons donated by ligands}

Vedclass · Accepted Answer

$36$

Vedclass · Answer

(D) The formula for the effective atomic number $(EAN)$ is given by: $EAN = Z - 	ext{oxidation state} + 	ext{number of electrons donated by ligands}$.In the complex $[Co(NH_3)_6]^{3+}$:$1$. The atomic number $(Z)$ of $Co$ is $27$.$2$. Let the oxidation state of $Co$ be $x$. Since $NH_3$ is a neutral ligand,$x + 6(0) = +3$,so $x = +3$.$3$. There are $6$ $NH_3$ ligands,each donating $2$ electrons,so the total number of electrons donated is $6 	imes 2 = 12$.$4$. $EAN = 27 - 3 + 12 = 36$.

What is the value of the effective atomic number $(EAN)$ of cobalt in the $[Co(NH_3)_6]^{3+}$ complex,given that the atomic number of $Co$ is $Z=27$?

Similar Questions

Effective Atomic Number $(EAN)$ of $Co$ in $Co_2(CO)_8$ will be

The Effective Atomic Number $(EAN)$ of $Ni$ in $Ni(CO)_4$ is:

In the brown ring complex,if $NO$ is considered as a neutral ligand,then the $EAN$ would:

The effective atomic number of $[A(NH_3)_6]Cl_3$ is $33$. What is the atomic number of element $A$?

The effective atomic number $(EAN)$ of $Co(CO)_4$ is $35$ and hence it is less stable. It attains stability by

Vedclass Test Series

Exam Paper Generator

Online Exam Module