What is the percentage of H_2O in Fe(CNS)_3 c | vedclass

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Question

(C) The molar mass of $Fe(CNS)_3 \cdot 3H_2O$ is calculated as follows:$Fe = 56$,$C = 12$,$N = 14$,$S = 32$,$H = 1$,$O = 16$.$Molar \ mass = 56 + 3

Vedclass · Accepted Answer

$19$

Vedclass · Answer

(C) The molar mass of $Fe(CNS)_3 \cdot 3H_2O$ is calculated as follows:$Fe = 56$,$C = 12$,$N = 14$,$S = 32$,$H = 1$,$O = 16$.$Molar \ mass = 56 + 3 	imes (12 + 14 + 32) + 3 	imes (2 	imes 1 + 16) = 56 + 3 	imes 58 + 3 	imes 18 = 56 + 174 + 54 = 284 \ g/mol$.The mass of $3H_2O$ is $3 	imes 18 = 54 \ g/mol$.The percentage of $H_2O$ is calculated as:$\frac{Mass \ of \ 3H_2O}{Total \ molar \ mass} 	imes 100 = \frac{54}{284} 	imes 100 \approx 19.01\%$.Thus,the correct option is $C$.

What is the percentage of $H_2O$ in $Fe(CNS)_3 \cdot 3H_2O$?

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