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(B) To find the percentage of chlorine by weight,we use the formula: $	ext{Percentage of Cl} = (	ext{Number of Cl atoms} 	imes 35.5 / 	ext{Molar m

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$IV < I < II < III$

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(B) To find the percentage of chlorine by weight,we use the formula: $	ext{Percentage of Cl} = (	ext{Number of Cl atoms} 	imes 35.5 / 	ext{Molar mass of compound}) 	imes 100$.$I.$ $DDT$ $(C_{14}H_9Cl_5)$: Molar mass $\approx 354.5 \ g/mol$. $\%Cl = (5 	imes 35.5 / 354.5) 	imes 100 \approx 50.06\%$.$II.$ Gammaxene $(C_6H_6Cl_6)$: Molar mass $\approx 291 \ g/mol$. $\%Cl = (6 	imes 35.5 / 291) 	imes 100 \approx 73.19\%$.$III.$ Carbon tetrachloride $(CCl_4)$: Molar mass $\approx 154 \ g/mol$. $\%Cl = (4 	imes 35.5 / 154) 	imes 100 \approx 92.20\%$.$IV.$ Chlorobenzene $(C_6H_5Cl)$: Molar mass $\approx 112.5 \ g/mol$. $\%Cl = (1 	imes 35.5 / 112.5) 	imes 100 \approx 31.55\%$.Comparing the percentages: $31.55\% (IV) Thus,the increasing order is $IV < I < II < III$.

Arrange the following compounds in the increasing order of percentage of chlorine by weight:
$I.$ $DDT$ $(C_{14}H_9Cl_5)$
$II.$ Gammaxene $(C_6H_6Cl_6)$
$III.$ Carbon tetrachloride $(CCl_4)$
$IV.$ Chlorobenzene $(C_6H_5Cl)$

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Arrange the following compounds in the increasing order of percentage of chlorine by weight:$I.$ $DDT$ $(C_{14}H_9Cl_5)$$II.$ Gammaxene $(C_6H_6Cl_6)$$III.$ Carbon tetrachloride $(CCl_4)$$IV.$ Chlorobenzene $(C_6H_5Cl)$