What is the type of hybridization in ICl_7? | vedclass

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(A) In $ICl_7$,the central iodine atom is bonded to $7$ chlorine atoms.Using the formula for steric number: $Steric \ Number = \frac{1}{2} [V + M - C

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$sp^3d^3$

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(A) In $ICl_7$,the central iodine atom is bonded to $7$ chlorine atoms.Using the formula for steric number: $Steric \ Number = \frac{1}{2} [V + M - C + A]$,where $V$ is the number of valence electrons of the central atom,$M$ is the number of monovalent atoms,$C$ is the cationic charge,and $A$ is the anionic charge.For $ICl_7$: $V = 7$ (iodine),$M = 7$ (chlorine atoms),$C = 0$,$A = 0$.$Steric \ Number = \frac{1}{2} [7 + 7] = 7$.$A$ steric number of $7$ corresponds to $sp^3d^3$ hybridization,which results in a pentagonal bipyramidal geometry.

What is the type of hybridization in $ICl_7$?

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