What is the product of the following reaction | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The reaction of $p$-hydroxybenzoic acid with excess $Br_2$ in $H_2O$ leads to electrophilic aromatic substitution. The $-OH$ group is a strongly a

Vedclass · Accepted Answer

$2,4,6-$Tribromophenol

Vedclass · Answer

(A) The reaction of $p$-hydroxybenzoic acid with excess $Br_2$ in $H_2O$ leads to electrophilic aromatic substitution. The $-OH$ group is a strongly activating and $o/p$-directing group,while the $-COOH$ group is a deactivating and $m$-directing group. Due to the strong activating effect of the $-OH$ group,bromination occurs at the positions ortho to the $-OH$ group. Since the para position is already occupied by the $-COOH$ group,the bromine atoms substitute the hydrogen atoms at the two ortho positions relative to the $-OH$ group. However,in the presence of excess $Br_2$ and $H_2O$,the $-COOH$ group can also be displaced by bromine (decarboxylation-bromination),leading to the formation of $2,4,6$-tribromophenol.

What is the product of the following reaction?

Similar Questions

In the following reaction sequence,identify $Q$:
$p\text{-Chloronitrobenzene}$ $\xrightarrow[\Delta, P]{NaOH} P$ $\xrightarrow{C_6H_5CH_2Cl} Q$

The major product of the following reaction sequence is:
Aniline $\xrightarrow[(i) NaNO_2, HCl, 273-278K]{(ii) H_2O, warm} \text{Product}$ $\xrightarrow[(iv) NaOH]{(iii) Br_2, (excess)} \text{Product}$ $\xrightarrow{(v) CH_3I} \text{Final Product}$

Aspirin is the acetylation product of .......

Identify $X$ and $Y$ in the following reactions:

The heating of phenyl methyl ether with $HI$ produces an aromatic compound $A$ which on treatment with conc. $HNO_3$ gives $B$. $A$ and $B$ respectively are

Vedclass Test Series

Exam Paper Generator

Online Exam Module