In the following reaction sequence,identify Q | vedclass

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(B) The reaction of $p$-chloronitrobenzene with $NaOH$ under heating and pressure is a nucleophilic aromatic substitution reaction. The strong electro

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$1-$Nitro$-4-$(benzyloxy)benzene

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(B) The reaction of $p$-chloronitrobenzene with $NaOH$ under heating and pressure is a nucleophilic aromatic substitution reaction. The strong electron-withdrawing $-NO_2$ group at the para position activates the ring towards nucleophilic attack,replacing the $-Cl$ atom with an $-OH$ group to form $p$-nitrophenol $(P)$.$P = p	ext{-Nitrophenol} (O_2N-C_6H_4-OH)$.In the second step,$p$-nitrophenol reacts with benzyl chloride $(C_6H_5CH_2Cl)$ in the presence of a base (implied). The phenoxide ion $(O_2N-C_6H_4-O^-)$ acts as a nucleophile and attacks the benzyl chloride via an $S_N2$ mechanism,resulting in the formation of an ether linkage.$O_2N-C_6H_4-O^- + C_6H_5CH_2Cl ightarrow O_2N-C_6H_4-O-CH_2-C_6H_5 + Cl^-$.The product $Q$ is $1	ext{-nitro-4-(benzyloxy)benzene}$ (also known as $4	ext{-nitrophenyl benzyl ether}$).

In the following reaction sequence,identify $Q$:
$p\text{-Chloronitrobenzene}$ $\xrightarrow[\Delta, P]{NaOH} P$ $\xrightarrow{C_6H_5CH_2Cl} Q$

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In the following reaction sequence,identify $Q$:$p\text{-Chloronitrobenzene}$ $\xrightarrow[\Delta, P]{NaOH} P$ $\xrightarrow{C_6H_5CH_2Cl} Q$