What is the product of the following reaction?

Product $A$ is

Match the List-$I$ with List-$II$:

List-$I$	List-$II$
$A$. Finkelstein reaction	$I$. $SbF_3$
$B$. Swarts reaction	$II$. $Na$,dry ether
$C$. Sandmeyer's reaction	$III$. $NaI$
$D$. Fittig reaction	$IV$. $Cu_2Cl_2$

Choose the correct answer from the options given below:

Alkyl halide $\xrightarrow[\text{Ether}]{Mg}$ Grignard Reagent $\xrightarrow{H_2O}$ Propane,then alkyl halide may be :-

In the following reaction sequence,$X$ and $Z$,respectively,are:
$CH_{3}CH_{2}CH_{2}-OH + PCl_{5} \rightarrow CH_{3}CH_{2}CH_{2}Cl + X + HCl$
$CH_{3}CH_{2}CH_{2}Cl \xrightarrow{alc. KOH, \Delta} Y$
$Y \xrightarrow{HBr, (C_{6}H_{5}CO)_{2}O_{2}} Z$

The reaction of toluene with $Cl_2$ in the presence of $FeCl_3$ gives $X$ and the reaction in the presence of light gives $Y.$ Thus,$X$ and $Y$ are