(C) $1$. When toluene reacts with $Cl_2$ in the presence of a Lewis acid catalyst like $FeCl_3$,electrophilic aromatic substitution occurs at the ring

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

$X = o-$ and $p-$chlorotoluene,$Y =$ Trichloromethyl benzene

(C) $1$. When toluene reacts with $Cl_2$ in the presence of a Lewis acid catalyst like $FeCl_3$,electrophilic aromatic substitution occurs at the ring (nuclear halogenation),resulting in $o-$ and $p-$chlorotoluene as $X$.$2$. When toluene reacts with $Cl_2$ in the presence of light $(hv)$,free radical substitution occurs at the side chain (side chain halogenation),resulting in benzyl chloride,benzal chloride,and finally trichloromethyl benzene (benzotrichloride) as $Y$.

Class 12 Chemistry Haloalkanes and Haloarenes Mix Examples-Haloalkanes and Haloarenes

Medium

The reaction of toluene with $Cl_2$ in the presence of $FeCl_3$ gives $X$ and the reaction in the presence of light gives $Y.$ Thus,$X$ and $Y$ are

AIPMT 2010 All AIPMT

A
$X =$ Benzal chloride,$Y = o-$chlorotoluene
B
$X = m-$chlorotoluene,$Y = p-$chlorotoluene
C
$X = o-$ and $p-$chlorotoluene,$Y =$ Trichloromethyl benzene
D
$X =$ Benzyl chloride,$Y = m-$chlorotoluene

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Haloalkanes and Haloarenes

Subtopic

Mix Examples-Haloalkanes and Haloarenes

Previous Year

AIPMT 2010 Paper All AIPMT years →

Complete the following reactions:
$(1)$ Isopropyl bromide $\xrightarrow[{KOH, \Delta}]{{\text{alcoholic}}} X$ $\xrightarrow[{peroxide}]{{HBr}} Y$
$(2)$ $n$-propyl alcohol $\xrightarrow[{443 \ K}]{{\text{Conc. } H_2SO_4}} X$ $\xrightarrow{{HBr}} Y$

Difficult

View Solution

Which of the following undergoes hydrolysis most easily?

Difficult

View Solution

Given below are two statements:
Statement $I$: $3$-phenylpropene reacts with $HBr$ and gives secondary alkyl bromide having a chiral carbon atom as the major product.
Statement $II$: Aryl chlorides and aryl cyanides can be prepared by Sandmeyer reaction as well as Gattermann reaction.

DifficultJEE MAIN 2026

View Solution

Identify the products formed and comment on the optical activity of the products for the following reaction: $3$-phenylcyclopent-$2$-en-$1$-one + $H_2$ $(2-3 \ atm)$ $\xrightarrow{10\% Pd/C, \text{Ethanol}}$ ?

Medium

View Solution

The major product for the following reaction is:

Difficult

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

The reaction of toluene with $Cl_2$ in the presence of $FeCl_3$ gives $X$ and the reaction in the presence of light gives $Y.$ Thus,$X$ and $Y$ are

Similar Questions

Complete the following reactions:$(1)$ Isopropyl bromide $\xrightarrow[{KOH, \Delta}]{{\text{alcoholic}}} X$ $\xrightarrow[{peroxide}]{{HBr}} Y$$(2)$ $n$-propyl alcohol $\xrightarrow[{443 \ K}]{{\text{Conc. } H_2SO_4}} X$ $\xrightarrow{{HBr}} Y$

Which of the following undergoes hydrolysis most easily?

Given below are two statements:Statement $I$: $3$-phenylpropene reacts with $HBr$ and gives secondary alkyl bromide having a chiral carbon atom as the major product.Statement $II$: Aryl chlorides and aryl cyanides can be prepared by Sandmeyer reaction as well as Gattermann reaction.

Identify the products formed and comment on the optical activity of the products for the following reaction: $3$-phenylcyclopent-$2$-en-$1$-one + $H_2$ $(2-3 \ atm)$ $\xrightarrow{10\% Pd/C, \text{Ethanol}}$ ?

The major product for the following reaction is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Complete the following reactions:
$(1)$ Isopropyl bromide $\xrightarrow[{KOH, \Delta}]{{\text{alcoholic}}} X$ $\xrightarrow[{peroxide}]{{HBr}} Y$
$(2)$ $n$-propyl alcohol $\xrightarrow[{443 \ K}]{{\text{Conc. } H_2SO_4}} X$ $\xrightarrow{{HBr}} Y$

Given below are two statements:
Statement $I$: $3$-phenylpropene reacts with $HBr$ and gives secondary alkyl bromide having a chiral carbon atom as the major product.
Statement $II$: Aryl chlorides and aryl cyanides can be prepared by Sandmeyer reaction as well as Gattermann reaction.