What are free radicals,carbanions,and carbocations? How are they formed?
(N/A) Free radicals,carbanions,and carbocations are highly reactive and unstable reaction intermediates formed during organic chemical reactions.
$1$. Carbocations and carbanions are formed by $heterolytic \ cleavage$,where the shared electron pair of a covalent bond is transferred to only one of the bonded atoms.
$2$. Free radicals are formed by $homolytic \ cleavage$,where each of the bonded atoms takes one electron from the shared pair of the covalent bond.
$1$. Carbocations and carbanions are formed by $heterolytic \ cleavage$,where the shared electron pair of a covalent bond is transferred to only one of the bonded atoms.
$2$. Free radicals are formed by $homolytic \ cleavage$,where each of the bonded atoms takes one electron from the shared pair of the covalent bond.
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List the reactive intermediates produced by the fission of a covalent bond and describe their main characteristics.
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View SolutionWhich of the following carbanions is the least stable?
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View SolutionWhich of the following orders regarding relative stability of free radicals is correct?
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View SolutionArrange the following free radicals in the correct order of their stability:
$(i)$ $CH_2=\dot{C}H$
$(ii)$ $\dot{C}H_3$
$(iii)$ $CH_3-\dot{C}H-CH_3$
$(iv)$ $(CH_3)_3\dot{C}$
$(i)$ $CH_2=\dot{C}H$
$(ii)$ $\dot{C}H_3$
$(iii)$ $CH_3-\dot{C}H-CH_3$
$(iv)$ $(CH_3)_3\dot{C}$
The increasing order of basicity for the following intermediates is (from weak to strong):
$(i)$ $(CH_3)_3C^{-}$
$(ii)$ $H_2C=CH-CH_2^{-}$
$(iii)$ $HC \equiv C^{-}$
$(iv)$ $CH_3^{-}$
$(v)$ $CN^{-}$
$(i)$ $(CH_3)_3C^{-}$
$(ii)$ $H_2C=CH-CH_2^{-}$
$(iii)$ $HC \equiv C^{-}$
$(iv)$ $CH_3^{-}$
$(v)$ $CN^{-}$
DifficultJEE MAIN 2020
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