What is the difference between the bond angle | vedclass

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(C) In the solid state,$PCl_5$ exists as $[PCl_4]^+ [PCl_6]^-$. The cation $[PCl_4]^+$ has a tetrahedral geometry with bond angles of $109^o 28'$.In t

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$0^o$

Vedclass · Answer

(C) In the solid state,$PCl_5$ exists as $[PCl_4]^+ [PCl_6]^-$. The cation $[PCl_4]^+$ has a tetrahedral geometry with bond angles of $109^o 28'$.In the solid state,$PBr_5$ exists as $[PBr_4]^+ Br^-$. The cation $[PBr_4]^+$ also has a tetrahedral geometry with bond angles of $109^o 28'$.Since both cationic species $[PCl_4]^+$ and $[PBr_4]^+$ are tetrahedral,their bond angles are identical.Therefore,the difference between the bond angles is $109^o 28' - 109^o 28' = 0^o$.

What is the difference between the bond angles in the cationic species of $PCl_5$ and $PBr_5$ in the solid state?

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