The bond length of the S=O bond is maximum in | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) According to $Bent's$ rule,more electronegative atoms prefer to occupy hybrid orbitals having less $s$-character,while less electronegative atoms

Vedclass · Accepted Answer

$SOBr_2$

Vedclass · Answer

(B) According to $Bent's$ rule,more electronegative atoms prefer to occupy hybrid orbitals having less $s$-character,while less electronegative atoms prefer orbitals with more $s$-character.In $SOX_2$ molecules,the $S=O$ bond has more $s$-character as the electronegativity of the halogen atom $(X)$ increases.As the electronegativity of $X$ decreases $(F > Cl > Br)$,the $s$-character in the $S-X$ bonds increases,which means the $s$-character in the $S=O$ bond decreases.Since bond length is inversely proportional to $s$-character,the $S=O$ bond length increases as the $s$-character in the $S=O$ bond decreases.Therefore,the $S=O$ bond length is maximum in $SOBr_2$ because $Br$ is the least electronegative among $F, Cl,$ and $Br$.

The bond length of the $S=O$ bond is maximum in which of the following compounds?

Similar Questions

Which of the following molecules do not exist?

Which of the following species is not a pseudo-halide?

Arrange the bonds in order of increasing ionic character in the molecules: $LiF, K_2O, N_2, SO_2$ and $ClF_3$.

Which of the following is a Lewis acid?

Which of the following molecules does not form in the $I^{st}$ excited state of the central atom?

Vedclass Test Series

Exam Paper Generator

Online Exam Module