What is the bond order of O_2^{2-}? | vedclass

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(C) The total number of electrons in $O_2^{2-}$ is $8 + 8 + 2 = 18$.According to the Molecular Orbital Theory,the electronic configuration of $O_2^{2-

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$1$

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(C) The total number of electrons in $O_2^{2-}$ is $8 + 8 + 2 = 18$.According to the Molecular Orbital Theory,the electronic configuration of $O_2^{2-}$ is: $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2 = \pi 2p_y^2, \pi^* 2p_x^2 = \pi^* 2p_y^2$.Number of bonding electrons $(N_b)$ = $10$.Number of antibonding electrons $(N_a)$ = $8$.Bond Order = $\frac{1}{2} (N_b - N_a) = \frac{1}{2} (10 - 8) = \frac{2}{2} = 1$.

What is the bond order of $O_2^{2-}$?

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