If Hund's Rule does not hold good,then which | vedclass

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(B) If $Hund's$ Rule is not followed,electrons will pair up in the lowest energy orbitals first.$B_2$ ($10$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \

Vedclass · Accepted Answer

$C_2, O_2$

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(B) If $Hund's$ Rule is not followed,electrons will pair up in the lowest energy orbitals first.$B_2$ ($10$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2, \pi 2p_y^0$. All electrons are paired,so it is diamagnetic.$C_2$ ($12$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2, \pi 2p_y^2$. All electrons are paired,so it is diamagnetic.$O_2$ ($16$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \sigma 2p_z^2, \pi 2p_x^2, \pi 2p_y^2, \pi^* 2p_x^2, \pi^* 2p_y^0$. All electrons are paired,so it is diamagnetic.$N_2$ ($14$ electrons): $\sigma 1s^2, \sigma^* 1s^2, \sigma 2s^2, \sigma^* 2s^2, \pi 2p_x^2, \pi 2p_y^2, \sigma 2p_z^2$. All electrons are paired,so it is diamagnetic.Since $C_2$ and $O_2$ are both diamagnetic under this assumption,option $B$ is the correct pair.

If $Hund's$ Rule does not hold good,then which of the following pairs is diamagnetic?

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| :--- | :--- |
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