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(C) In circuit $X$,both diodes $D_1$ and $D_2$ are forward biased,so both conduct current.The two resistors of $4 \ \Omega$ each are connected in para

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$4 \ A, 2 \ A$

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(C) In circuit $X$,both diodes $D_1$ and $D_2$ are forward biased,so both conduct current.The two resistors of $4 \ \Omega$ each are connected in parallel.The equivalent resistance $R_{eq}$ is given by $\frac{1}{R_{eq}} = \frac{1}{4} + \frac{1}{4} = \frac{2}{4} = \frac{1}{2}$,so $R_{eq} = 2 \ \Omega$.The total current $I_X = \frac{V}{R_{eq}} = \frac{8 \ V}{2 \ \Omega} = 4 \ A$.In circuit $Y$,diode $D_1$ is forward biased,but diode $D_2$ is reverse biased.Therefore,only diode $D_1$ conducts current.The effective resistance in the circuit is $4 \ \Omega$.The total current $I_Y = \frac{V}{R} = \frac{8 \ V}{4 \ \Omega} = 2 \ A$.Thus,the currents are $4 \ A$ and $2 \ A$ respectively.

What are the values of the currents flowing in each of the following diode circuits $X$ and $Y$ respectively? (Assume that the diodes are ideal)

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