What is the configuration of the two chiral c | vedclass

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(C) To determine the configuration of the chiral centers,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules.For the chiral center at $C-2$ (the uppe

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$2S, 3R$

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(C) To determine the configuration of the chiral centers,we use the Cahn-Ingold-Prelog $(CIP)$ priority rules.For the chiral center at $C-2$ (the upper one attached to $COOH$,$CH_3$,$H$,and the rest of the chain):$1$. Priority $1$: $-COOH$ $(-C(=O)OH)$$2$. Priority $2$: $-CH(OH)CH_2CH_2OH$ (the lower chiral center group)$3$. Priority $3$: $-CH_3$$4$. Priority $4$: $-H$Since the lowest priority group $(-H)$ is on a horizontal bond,we reverse the result. The sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is clockwise $(R)$,so reversing it gives $S$. Thus,$C-2$ is $2S$.For the chiral center at $C-3$ (the lower one attached to $OH$,$H$,$CH_2CH_2OH$,and the upper group):$1$. Priority $1$: $-OH$$2$. Priority $2$: $-CH(CH_3)COOH$ (the upper chiral center group)$3$. Priority $3$: $-CH_2CH_2OH$$4$. Priority $4$: $-H$Since the lowest priority group $(-H)$ is on a horizontal bond,we reverse the result. The sequence $1$ $\rightarrow 2$ $\rightarrow 3$ is counter-clockwise $(S)$,so reversing it gives $R$. Thus,$C-3$ is $3R$.Therefore,the configuration is $2S, 3R$.

$(I)$ Optical Activity	$(II)$ Form	$(III)$ Sign	$(IV)$ Rotation
$(A)$ Dextrorotatory	$d$	$(+)$	Right
$(B)$ Laevorotatory	$l$	$(-)$	Left
$(C)$ Optically Inactive (Racemic)	$dl$	$(\pm)$	Zero rotation

What is the configuration of the two chiral centers in the given molecule?

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