The number of meso form of the given compound | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

if terminals are same and number of chiral carbon atoms are three, then no. of meso-form

$=2^{\frac{\mathrm{n}-1}{2}}=2^{\frac{3-1}{2}}=2$

$\mat

Vedclass · Accepted Answer

$2$

Vedclass · Answer

if terminals are same and number of chiral carbon atoms are three, then no. of meso-form

$=2^{\frac{\mathrm{n}-1}{2}}=2^{\frac{3-1}{2}}=2$

$\mathrm{n}=\mathrm{no} .$ of chiral $C-$atoms

The number of meso form of the given compound is

$\begin{array}{*{20}{c}}
{C{H_3} - CH - CH - CH - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,} \\
{OH\,\,\,\,\,\,\,OH\,\,\,\,\,OH\,\,}
\end{array}$

Similar Questions

Total number of stereoisomers of the compound $1$ -bromo- $3$ -chlorocyclobutane is

In which of the following compound, possess plane of symmetry as well as centre of symmetry?

It is possible to distinguish between optical isomers by

Pure $(S)-2$ -butanol has a specific rotation of $+ 13.52$ degrees. A sample of $2$ -butanol prepared in the lab and purified by distillation has a calculated specific rotation of $+6.76$ degrees. What can you conclude about the composition ?

The separation of a racemic mixture into pure enantiomers is termed as

The number of meso form of the given compound is $\begin{array}{*{20}{c}} {C{H_3} - CH - CH - CH - C{H_3}} \\ {|\,\,\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,|\,\,\,\,\,} \\ {OH\,\,\,\,\,\,\,OH\,\,\,\,\,OH\,\,} \end{array}$