What are X, Y, Z in the following reaction se | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) Step $1$: Oxidation of $but-2-ene$ $(CH_3-CH=CH-CH_3)$ with acidic $KMnO_4$ $(X)$ gives ethanoic acid $(CH_3COOH)$. Step $2$: Ethanoic acid reacts

Vedclass · Accepted Answer

$KMnO_4 / H^{+} ; SOCl_2 ;$ Acetophenone

Vedclass · Answer

(A) Step $1$: Oxidation of $but-2-ene$ $(CH_3-CH=CH-CH_3)$ with acidic $KMnO_4$ $(X)$ gives ethanoic acid $(CH_3COOH)$. Step $2$: Ethanoic acid reacts with $SOCl_2$ $(Y)$ to form ethanoyl chloride $(CH_3COCl)$. Step $3$: Ethanoyl chloride reacts with benzene in the presence of anhydrous $AlCl_3$ (Friedel-Crafts acylation) to form acetophenone ($Z$,$C_6H_5COCH_3$). Therefore,$X = KMnO_4 / H^{+}$,$Y = SOCl_2$,and $Z = 	ext{Acetophenone}$.

What are $X, Y, Z$ in the following reaction sequence?
$CH_3-CH=CH-CH_3$ $\xrightarrow{X} CH_3COOH$ $\xrightarrow{Y} CH_3COCl$ $\xrightarrow[\text{Anhy. } AlCl_3]{\text{Benzene}} Z$

Similar Questions

Product $(A)$ of the reaction is:

The products obtained in the given reactions are shown below. The number of possible products for $x$ and $y$ are:

Maximum enol content is in

Identify the product $Y$ in the following reaction sequence:
$Benzene + CH_3CH_2CH_2Cl$ $\xrightarrow{AlCl_3} X$ $\xrightarrow{KMnO_4} Y$

Arrange the following labelled hydrogens in decreasing order of acidity.

Vedclass Test Series

Exam Paper Generator

Online Exam Module

What are $X, Y, Z$ in the following reaction sequence? $CH_3-CH=CH-CH_3$ $\xrightarrow{X} CH_3COOH$ $\xrightarrow{Y} CH_3COCl$ $\xrightarrow[\text{Anhy. } AlCl_3]{\text{Benzene}} Z$