What are X and Y in the following reactions?C | vedclass

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(B) For the first reaction:$CH_2O$ (formaldehyde) reacts with a Grignard reagent $(RMgBr)$ followed by hydrolysis to form a primary alcohol. The produ

Vedclass · Accepted Answer

$X = CH_3CH_2CH_2MgBr, Y = CH_3-CO-CH_3$

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(B) For the first reaction:$CH_2O$ (formaldehyde) reacts with a Grignard reagent $(RMgBr)$ followed by hydrolysis to form a primary alcohol. The product is $CH_3CH_2CH_2CH_2OH$ (butan$-1-$ol). The Grignard reagent must be $CH_3CH_2CH_2MgBr$ (propylmagnesium bromide).For the second reaction:$Y$ reacts with $C_2H_5MgBr$ followed by hydrolysis to form $CH_3CH_2C(CH_3)_2OH$ ($2$-methylbutan$-2-$ol). This is a tertiary alcohol. The reaction of a ketone with a Grignard reagent produces a tertiary alcohol. Comparing the structure,$Y$ must be $CH_3COCH_3$ (acetone or propanone).Thus,$X = CH_3CH_2CH_2MgBr$ and $Y = CH_3COCH_3$.

What are $X$ and $Y$ in the following reactions?
$CH_2O \xrightarrow[(ii) H_3O^+]{(i) X} CH_3(CH_2)_2CH_2OH$
$Y \xrightarrow[(ii) H_3O^+]{(i) C_2H_5MgBr} CH_3CH_2C(CH_3)_2OH$

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$CH_3-CH_2-C(Ph)(OH)-CH_3$ can not be prepared by:

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What are $X$ and $Y$ in the following reactions?$CH_2O \xrightarrow[(ii) H_3O^+]{(i) X} CH_3(CH_2)_2CH_2OH$$Y \xrightarrow[(ii) H_3O^+]{(i) C_2H_5MgBr} CH_3CH_2C(CH_3)_2OH$