Wax is coated on the inner wall of a capillary tube and the tube is then dipped in water. Then,compared to the unwaxed capillary,the angle of contact $\theta$ and the height $h$ up to which water rises change. These changes are:

Three liquids of densities $\rho_1, \rho_2$ and $\rho_3$ (with $\rho_1 > \rho_2 > \rho_3$),having the same value of surface tension $T$,rise to the same height in three identical capillaries. The angles of contact $\theta_1, \theta_2$ and $\theta_3$ obey:

The water rises in the capillary to a height of $10\, cm$. If the surface tension of water is $73 \times 10^{-3}\, N/m$,density is $10^3\, kg/m^3$ and $g = 9.8\, m/s^2$,then find the radius of the capillary. (in $, cm$)

$A$ $U$-tube is such that the diameter of one limb is $0.4\,mm$ and that of the other is $d\,mm$. If the surface tension of water contained in the tube is $0.07\,N/m$ and the difference in the levels of liquid in the limbs is $3.6\,cm$,then the value of $d$ is:

Water rises in a capillary tube of radius $r$ up to a height $h$. The mass of water in the capillary is $m$. The mass of water that will rise in a capillary of radius $r/3$ will be:

Surface tension of two liquids (having same densities),$T_1$ and $T_2$,are measured using the capillary rise method utilizing two tubes with inner radii of $r_1$ and $r_2$ where $r_1 > r_2$. The measured liquid heights in these tubes are $h_1$ and $h_2$ respectively. [Ignore the weight of the liquid above the lowest point of the meniscus]. If $T_1 = T_2$,which of the following relations is satisfied?