Water rises in a capillary tube of radius r u | vedclass

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(B) The height of water rising in a capillary tube is given by $h = \frac{2T \cos 	heta}{r ho g}$.For water,$\cos 	heta \approx 1$,so $h \propto \

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$m/3$

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(B) The height of water rising in a capillary tube is given by $h = \frac{2T \cos 	heta}{r ho g}$.For water,$\cos 	heta \approx 1$,so $h \propto \frac{1}{r}$.If the new radius is $r' = r/3$,the new height $h'$ will be $h' = \frac{h}{r/3} \cdot r = 3h$.The mass of water in the capillary is given by $m = V ho = (\pi r^2 h) ho$.For the new capillary,the mass $m'$ is $m' = \pi (r')^2 h' ho$.Substituting $r' = r/3$ and $h' = 3h$:$m' = \pi (r/3)^2 (3h) ho = \pi (r^2/9) (3h) ho = \frac{1}{3} (\pi r^2 h ho) = \frac{m}{3}$.

Water rises in a capillary tube of radius $r$ up to a height $h$. The mass of water in the capillary is $m$. The mass of water that will rise in a capillary of radius $r/3$ will be:

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