Water rises in a capillary tube up to a heigh | vedclass

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(A) When a capillary tube is tilted at an angle $\alpha$ with the vertical,the vertical height $h$ of the water column remains constant because it dep

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$\frac{8}{\sqrt{3}} \, cm$

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(A) When a capillary tube is tilted at an angle $\alpha$ with the vertical,the vertical height $h$ of the water column remains constant because it depends on the surface tension,radius of the tube,and density of the liquid.The length of the water column $\ell$ along the tube is related to the vertical height $h$ by the relation:$\cos \alpha = \frac{h}{\ell}$Therefore,the length of the water column is:$\ell = \frac{h}{\cos \alpha}$Given $h = 4 \, cm$ and $\alpha = 30^{\circ}$:$\ell = \frac{4}{\cos 30^{\circ}}$Since $\cos 30^{\circ} = \frac{\sqrt{3}}{2}$:$\ell = \frac{4}{\frac{\sqrt{3}}{2}} = \frac{8}{\sqrt{3}} \, cm$

Water rises in a capillary tube up to a height of $4 \, cm$. If it is tilted to $30^{\circ}$ from the vertical,then the length of the water column in it will be

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