Water is flowing with a velocity of 2,m/s in | vedclass

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(C) Using the equation of continuity: $A_1 V_1 = A_2 V_2$.Given: $A_1 = 2 	imes 10^{-2}\, m^2$,$V_1 = 2\, m/s$,$A_2 = 0.01\, m^2 = 1 	imes 10^{-2}\,

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$3.4 	imes 10^4$

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(C) Using the equation of continuity: $A_1 V_1 = A_2 V_2$.Given: $A_1 = 2 	imes 10^{-2}\, m^2$,$V_1 = 2\, m/s$,$A_2 = 0.01\, m^2 = 1 	imes 10^{-2}\, m^2$.$(2 	imes 10^{-2}) 	imes 2 = (1 	imes 10^{-2}) 	imes V_2 \implies V_2 = 4\, m/s$.Using Bernoulli's equation for a horizontal pipe $(h_1 = h_2)$: $P_1 + \frac{1}{2} ho V_1^2 = P_2 + \frac{1}{2} ho V_2^2$.Given $ho = 10^3\, kg/m^3$ and $P_1 = 4 	imes 10^4\, Pa$.$4 	imes 10^4 + \frac{1}{2} 	imes 10^3 	imes (2)^2 = P_2 + \frac{1}{2} 	imes 10^3 	imes (4)^2$.$40000 + 2000 = P_2 + 8000$.$P_2 = 42000 - 8000 = 34000\, Pa = 3.4 	imes 10^4\, Pa$.

Water is flowing with a velocity of $2\,m/s$ in a horizontal pipe where the cross-sectional area is $2 \times 10^{-2}\, m^2$ at a pressure of $4 \times 10^4\, Pa$. The pressure at a cross-section of area $0.01\, m^2$ in $Pa$ will be:

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