In the given (V-T) diagram,what is the relati | vedclass

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(D) From the ideal gas equation,$PV = nRT$,we can write $V = (\frac{nR}{P})T$.Comparing this with the equation of a straight line $y = mx$,where $y =

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$P_2 < P_1$

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(D) From the ideal gas equation,$PV = nRT$,we can write $V = (\frac{nR}{P})T$.Comparing this with the equation of a straight line $y = mx$,where $y = V$ and $x = T$,the slope $m$ is given by $m = \frac{nR}{P}$.Since the slope is inversely proportional to pressure $(m \propto \frac{1}{P})$,a smaller slope corresponds to a higher pressure.In the $(V-T)$ diagram,the line for $P_1$ makes a smaller angle $	heta_1$ with the $T$-axis compared to the line for $P_2$ (where $	heta_2 > 	heta_1$).Therefore,the slope of the line for $P_1$ is less than the slope of the line for $P_2$.Since $	ext{slope}_1  P_2$ or $P_2 < P_1$.

In the given $(V-T)$ diagram,what is the relation between pressure $P_1$ and $P_2$?

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