Water in a river 20 m deep is flowing at a s | vedclass

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(D) The shearing stress $	au$ is given by the formula: $	au = \eta \left( \frac{dv}{dx} ight)$.Here,$\eta = 10^{-3} \ SI \ units$ is the coefficie

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$0.5 	imes 10^{-3}$

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(D) The shearing stress $	au$ is given by the formula: $	au = \eta \left( \frac{dv}{dx} ight)$.Here,$\eta = 10^{-3} \ SI \ units$ is the coefficient of viscosity.The velocity gradient $\frac{dv}{dx}$ is calculated as the velocity $v$ divided by the depth $x$.Given $v = 10 \ ms^{-1}$ and $x = 20 \ m$,we have $\frac{dv}{dx} = \frac{10}{20} = 0.5 \ s^{-1}$.Substituting these values into the formula:$	au = 10^{-3} 	imes 0.5 = 0.5 	imes 10^{-3} \ Nm^{-2}$.

Water in a river $20 \ m$ deep is flowing at a speed of $10 \ ms^{-1}$. The shearing stress between the horizontal layers of water in the river in $Nm^{-2}$ is (Coefficient of viscosity of water $= 10^{-3} \ SI \ units$)

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