Water (of density $\varrho$) flows steadily through a horizontal pipe of variable cross-section. If the pressure of water is $P$ at a point where the flow speed is $V$,then the pressure at another point where the flow speed becomes $3V$ is:

  • A
    $P + 4 \varrho V^2$
  • B
    $P - 4 \varrho V^2$
  • C
    $P + 8 \varrho V^2$
  • D
    $P - 8 \varrho V^2$

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Water flows in a horizontal tube (see figure). The pressure of water changes by $700 \; Nm^{-2}$ between $A$ and $B$ where the area of cross-section are $40 \; cm^{2}$ and $20 \; cm^{2},$ respectively. Find the rate of flow of water through the tube in $cm^{3} / s$. (Density of water $= 1000 \; kgm^{-3}$)

According to Bernoulli's equation $\frac{P}{\rho g} + h + \frac{v^2}{2g} = \text{constant}$,the terms $\frac{P}{\rho g}$,$h$,and $\frac{v^2}{2g}$ are generally called respectively:

Prove Bernoulli's Principle.

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