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(D) Let $H$ be the height of the water level from the bottom,$h$ be the height of the hole from the bottom,$A$ be the cross-sectional area,$M$ be the

Vedclass · Accepted Answer

$11$

Vedclass · Answer

(D) Let $H$ be the height of the water level from the bottom,$h$ be the height of the hole from the bottom,$A$ be the cross-sectional area,$M$ be the total mass on the piston $(M = 5\ kg + 45\ kg = 50\ kg)$,and $ho$ be the density of water $(10^3\ kg/m^3)$.Applying Bernoulli's equation between the top surface of the water and the hole:$P_{atm} + \frac{Mg}{A} + ho gH = P_{atm} + \frac{1}{2}ho v^2 + ho gh$$\frac{1}{2}ho v^2 = ho g(H - h) + \frac{Mg}{A}$Given $H = 7\ m$,$h = 1\ m$,$M = 50\ kg$,$A = 1\ m^2$,$g = 10\ m/s^2$,$ho = 10^3\ kg/m^3$:$\frac{1}{2} 	imes 10^3 	imes v^2 = 10^3 	imes 10 	imes (7 - 1) + \frac{50 	imes 10}{1}$$500 v^2 = 60000 + 500$$500 v^2 = 60500$$v^2 = 121$$v = 11\ m/s$

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