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(D) The mean kinetic energy of a gas molecule depends only on the absolute temperature $T$ and is given by the formula $KE_{avg} = \frac{3}{2} k_B T$,

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$1:1$

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(D) The mean kinetic energy of a gas molecule depends only on the absolute temperature $T$ and is given by the formula $KE_{avg} = \frac{3}{2} k_B T$,where $k_B$ is the Boltzmann constant.Since both gases are at the same temperature $T$,the mean kinetic energy per molecule for both hydrogen and oxygen will be identical.Therefore,the ratio of the mean kinetic energies is $\frac{KE_{H_2}}{KE_{O_2}} = \frac{\frac{3}{2} k_B T}{\frac{3}{2} k_B T} = 1:1$.The volume and mass of the gases do not affect the mean kinetic energy per molecule.

Vessel $A$ is filled with hydrogen while vessel $B,$ whose volume is twice that of $A,$ is filled with the same mass of oxygen at the same temperature. The ratio of the mean kinetic energies of hydrogen and oxygen is

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