(B) To verify if $x = \frac{1}{2}$ is a solution,substitute the value into the quadratic equation $2x^{2} - 6x + 3 = 0$.Substitute $x = \frac{1}{2}$:$

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(B) To verify if $x = \frac{1}{2}$ is a solution,substitute the value into the quadratic equation $2x^{2} - 6x + 3 = 0$.Substitute $x = \frac{1}{2}$:$2(\frac{1}{2})^{2} - 6(\frac{1}{2}) + 3$$= 2(\frac{1}{4}) - 3 + 3$$= \frac{1}{2} - 3 + 3$$= \frac{1}{2}$Since the result is $\frac{1}{2}$ and not $0$,$x = \frac{1}{2}$ is not a solution to the given quadratic equation.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

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Verify whether the given value of $x$ is a solution of the quadratic equation or not: $2x^{2} - 6x + 3 = 0$; $x = \frac{1}{2}$.

A
Yes
B
No
C
Cannot be determined
D
None of these

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Mix Examples - Quadratic Equations

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Verify whether the given value of $x$ is a solution of the quadratic equation or not: $2x^{2} - 6x + 3 = 0$; $x = \frac{1}{2}$.

Similar Questions

Examine whether the following equation is quadratic or not: $9x = 3x^3$.

Find the roots of the quadratic equation using the quadratic formula:$x^{2}+2 \sqrt{2} x-6=0$

Verify whether the given value of $x = 2$ is a solution of the quadratic equation $\frac{1}{x+4} - \frac{1}{x-7} = \frac{11}{30}$ or not.

Find the roots of the following quadratic equation using the quadratic formula,if they exist: $\frac{1}{x+1} + \frac{2}{x+2} = \frac{4}{x+4}$; $(x \neq -1, -2, -4)$

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Find the roots of the quadratic equation using the quadratic formula:
$x^{2}+2 \sqrt{2} x-6=0$