(B) To verify if $x=2$ is a solution,substitute $x=2$ into the given quadratic equation: $(x-2)(x+3)+1=0$.Substituting $x=2$:$(2-2)(2+3)+1 = (0)(5)+1

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(B) To verify if $x=2$ is a solution,substitute $x=2$ into the given quadratic equation: $(x-2)(x+3)+1=0$.Substituting $x=2$:$(2-2)(2+3)+1 = (0)(5)+1 = 0+1 = 1$.Since the result is $1$ and not $0$,the left-hand side is not equal to the right-hand side.Therefore,$x=2$ is not a solution of the given quadratic equation.

Class 10 Mathematics Quadratic Equations Mix Examples - Quadratic Equations

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Verify whether the given value of $x$ is a solution of the quadratic equation or not: $(x-2)(x+3)+1=0$; $x=2$.

A
Yes,it is a solution.
B
No,it is not a solution.
C
It is a root of the equation.
D
The equation is not defined at $x=2$.

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Mix Examples - Quadratic Equations

Find the discriminant of the following quadratic equation: $x^{2}-5x-14=0$.

Easy

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Examine whether the following equation is quadratic or not: $x^{2}-3=\frac{2}{x}$

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The value of the discriminant of the quadratic equation $x^{2}-8x+15=0$ is ...... .

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Solve the following equation using the method of factorization and write its solution set: $\frac{1}{x-2}+\frac{1}{x+3}=\frac{7}{2x}$ $(x \neq 2, x \neq -3, x \neq 0)$

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The standard form of a quadratic equation in one variable is $\ldots \ldots \ldots \ldots . .$

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Verify whether the given value of $x$ is a solution of the quadratic equation or not: $(x-2)(x+3)+1=0$; $x=2$.

Similar Questions

Find the discriminant of the following quadratic equation: $x^{2}-5x-14=0$.

Examine whether the following equation is quadratic or not: $x^{2}-3=\frac{2}{x}$

The value of the discriminant of the quadratic equation $x^{2}-8x+15=0$ is ...... .

Solve the following equation using the method of factorization and write its solution set: $\frac{1}{x-2}+\frac{1}{x+3}=\frac{7}{2x}$ $(x \neq 2, x \neq -3, x \neq 0)$

The standard form of a quadratic equation in one variable is $\ldots \ldots \ldots \ldots . .$

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