The velocity-time curve for a body projected vertically upwards is:

$A$ body is thrown vertically upwards with a velocity of $19.6 \, ms^{-1}$. The position of the body after $4 \, s$ will be

$A$ body projected vertically upwards with a certain speed from the top of a tower reaches the ground in $t_1$. If it is projected vertically downwards from the same point with the same speed,it reaches the ground in $t_2$. Time required to reach the ground,if it is dropped from the top of the tower,is:

$A$ particle is thrown vertically upwards with a velocity of $4\,ms^{-1}$. The ratio of its accelerations after $1\,s$ and $2\,s$ of its motion is

Two spheres of same size,one of mass $2\, kg$ and another of mass $4\, kg$,are dropped simultaneously from the top of Qutab Minar (height $= 72\, m$). When they are $1\, m$ above the ground,the two spheres have the same

$A$ stone is dropped from a height of $100 \ m$,while another one is projected vertically upwards from the ground with a velocity of $25 \ m/s$ at the same time. The time in seconds after which they will have the same height is (acceleration due to gravity,$g = 10 \ m/s^2$):