The value of the temperature gradient is 80,^ | vedclass

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Question

(A) The temperature gradient is defined as the rate of change of temperature with respect to distance, given by the formula: $\frac{T_{H} - T_{C}}{L}

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$-10\,^{\circ}C$

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(A) The temperature gradient is defined as the rate of change of temperature with respect to distance, given by the formula: $\frac{T_{H} - T_{C}}{L} = 80\,^{\circ}C/m$.Here, $T_{H} = 30\,^{\circ}C$ (temperature of the hot end), $L = 0.5\,m$ (length of the rod), and $T_{C}$ is the temperature of the cold end.Substituting the values into the equation:$\frac{30 - T_{C}}{0.5} = 80$$30 - T_{C} = 80 	imes 0.5$$30 - T_{C} = 40$$T_{C} = 30 - 40$$T_{C} = -10\,^{\circ}C$.Therefore, the temperature of the cold end is $-10\,^{\circ}C$.

The value of the temperature gradient is $80\,^{\circ}C/m$ on a rod of $0.5\,m$ length. If the temperature of the hot end is $30\,^{\circ}C$, what is the temperature of the cold end?

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