The value of n in the given reaction is: | vedclass

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(A) The given compound is $1,3,5$-trimethoxybenzene. When an ether reacts with excess $HI$,the $C-O$ bond is cleaved to form an alcohol and an alkyl i

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(A) The given compound is $1,3,5$-trimethoxybenzene. When an ether reacts with excess $HI$,the $C-O$ bond is cleaved to form an alcohol and an alkyl iodide. In the case of $1,3,5$-trimethoxybenzene,there are three methoxy $(-OCH_3)$ groups attached to the benzene ring. Each methoxy group reacts with one molecule of $HI$ to form a phenolic $-OH$ group and one molecule of methyl iodide $(CH_3I)$. The reaction is: $C_6H_3(OCH_3)_3 + 3HI \rightarrow C_6H_3(OH)_3 + 3CH_3I$. Thus,$3$ moles of $HI$ are required for the complete cleavage of the three methoxy groups. Therefore,the value of $n$ is $3$.

Column-$I$ (Product)	Column-$II$ (Reagent)
$A$. Mainly $p$-bromoanisole	$i$. Anhydrous $AlCl_3$,$CH_3COCl$
$B$. $4$-nitroanisole	$ii$. $CH_3Cl$,anhydrous $AlCl_3$ in $CS_2$
$C$. $4$-methoxytoluene	$iii$. $Br_2$ in ethanoic acid
$D$. $4$-methoxyacetophenone	$iv$. Mixture of conc. $H_2SO_4$ and $HNO_3$

The value of $n$ in the given reaction is:

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