In the given reactionC_6H_5 - O - CH_2 - CH_3 | vedclass

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(B) The reaction of an alkyl aryl ether with excess $HI$ involves the cleavage of the $C_{aryl}-O$ and $C_{alkyl}-O$ bonds.$1$. The $C_{alkyl}-O$ bond

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$C_6H_5OH$ and $CH_3CH_2I$

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(B) The reaction of an alkyl aryl ether with excess $HI$ involves the cleavage of the $C_{aryl}-O$ and $C_{alkyl}-O$ bonds.$1$. The $C_{alkyl}-O$ bond is cleaved to form an alkyl halide $(CH_3CH_2I)$ and a phenol $(C_6H_5OH)$.$2$. Since $HI$ is in excess,the phenol $(C_6H_5OH)$ does not react further with $HI$ to form iodobenzene because the $C_{aryl}-O$ bond has partial double bond character due to resonance,making it difficult to break.$3$. Therefore,the products are $C_6H_5OH$ and $CH_3CH_2I$.

In the given reaction
$C_6H_5 - O - CH_2 - CH_3 \xrightarrow{\text{Excess } HI / \Delta} [X] + [Y]$
$[X]$ and $[Y]$ will respectively be

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In the given reaction$C_6H_5 - O - CH_2 - CH_3 \xrightarrow{\text{Excess } HI / \Delta} [X] + [Y]$$[X]$ and $[Y]$ will respectively be