(D) Mole fraction $(x_i)$ is defined as the ratio of the number of moles of a specific component $(n_i)$ to the total number of moles of all component

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(D) Mole fraction $(x_i)$ is defined as the ratio of the number of moles of a specific component $(n_i)$ to the total number of moles of all components in the solution $(n_{total})$.Mathematically,$x_i = \frac{n_i}{n_{total}}$.Since it is a ratio of two quantities having the same unit (moles),the units cancel out.Therefore,mole fraction is a dimensionless quantity.

Class 12 Chemistry Solutions Method of expressing concentration of solution

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The unit of mole fraction is:

A
Moles/litre
B
Moles/litre$^2$
C
Moles-litre
D
Dimensionless

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Method of expressing concentration of solution

If the mole fraction of the solute in liquid naphthalene $(C_{10}H_{8})$ is $0.2$,then the molality of the solution will be ............ $m$.

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The number of molecules present in $100 \ mL$ of a urea solution is $6.02 \times 10^{23}$. What is the molarity $(M)$ of the urea solution?

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What type of solution is obtained from an amalgam of mercury with sodium?

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The molality of an aqueous solution of glucose is $1.0 \ m$. The mole fraction of glucose is approximately ........

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Assertion $(A)$: Molality of a solution increases with temperature.
Reason $(R)$: Molality expression does not involve any volume term.

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The unit of mole fraction is:

Similar Questions

If the mole fraction of the solute in liquid naphthalene $(C_{10}H_{8})$ is $0.2$,then the molality of the solution will be ............ $m$.

The number of molecules present in $100 \ mL$ of a urea solution is $6.02 \times 10^{23}$. What is the molarity $(M)$ of the urea solution?

What type of solution is obtained from an amalgam of mercury with sodium?

The molality of an aqueous solution of glucose is $1.0 \ m$. The mole fraction of glucose is approximately ........

Assertion $(A)$: Molality of a solution increases with temperature.Reason $(R)$: Molality expression does not involve any volume term.

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Assertion $(A)$: Molality of a solution increases with temperature.
Reason $(R)$: Molality expression does not involve any volume term.