(D) $1$. Calculate the number of moles of urea $(n)$: $n = \frac{\text{Number of molecules}}{\text{Avogadro's number}} = \frac{6.02 \times 10^{23}}{6.

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(D) $1$. Calculate the number of moles of urea $(n)$: $n = \frac{\text{Number of molecules}}{\text{Avogadro's number}} = \frac{6.02 \times 10^{23}}{6.02 \times 10^{23}} = 1 \ mol$. $2$. Convert the volume of the solution to liters: $V = 100 \ mL = 0.1 \ L$. $3$. Calculate the molarity $(M)$: $M = \frac{n}{V(L)} = \frac{1 \ mol}{0.1 \ L} = 10 \ M$.

Class 12 Chemistry Solutions Method of expressing concentration of solution

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The number of molecules present in $100 \ mL$ of a urea solution is $6.02 \times 10^{23}$. What is the molarity $(M)$ of the urea solution?

A
$0.001$
B
$0.01$
C
$0.02$
D
$10$

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Method of expressing concentration of solution

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The number of molecules present in $100 \ mL$ of a urea solution is $6.02 \times 10^{23}$. What is the molarity $(M)$ of the urea solution?

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