The unit for the radioactive decay constant i | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The rate of radioactive decay is given by the equation: $-\frac{dN}{dt} = \lambda N$,where $\lambda$ is the decay constant.Rearranging for $\lambd

Vedclass · Accepted Answer

$Time^{-1}$

Vedclass · Answer

(A) The rate of radioactive decay is given by the equation: $-\frac{dN}{dt} = \lambda N$,where $\lambda$ is the decay constant.Rearranging for $\lambda$,we get $\lambda = -\frac{dN/dt}{N}$.Since $dN/dt$ represents the number of disintegrations per unit time and $N$ is the number of nuclei,the unit of $\lambda$ is $	ext{time}^{-1}$ (e.g.,$s^{-1}$,$min^{-1}$,or $year^{-1}$).Therefore,the correct option is $A$.

The unit for the radioactive decay constant is:

Similar Questions

$2 \text{ g}$ of a radioactive sample having a half-life of $15$ days was synthesized on $1^{st}$ Jan $2009$. The amount of the sample left behind on $1^{st}$ March $2009$ (including both the days) is: (in $\text{ g}$)

$A$ certain nuclide has a half-life of $25 \ min$. If one starts with $100 \ g$ of it,how much of it will remain at the end of $100 \ min$?

The half-life of a radionuclide is $69.3 \text{ minutes}$. What is its average life (in minutes)?

If the quantity of a radioactive element is doubled,then its rate of disintegration per unit time will be

If the half-life of a certain radioactive nucleus is $1000 \ s,$ the disintegration constant is

Vedclass Test Series

Exam Paper Generator

Online Exam Module