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(B) Stress is defined as the force applied per unit area: $	ext{Stress} = \frac{F}{A} = \frac{F}{\pi r^2}$.Since both wires are stretched by the same

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four times

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(B) Stress is defined as the force applied per unit area: $	ext{Stress} = \frac{F}{A} = \frac{F}{\pi r^2}$.Since both wires are stretched by the same load,the force $F$ is constant.Therefore,$	ext{Stress} \propto \frac{1}{r^2}$.Given that the radius of wire $A$ is double the radius of wire $B$,we have $r_A = 2r_B$.Comparing the stresses $S_A$ and $S_B$:$\frac{S_B}{S_A} = \frac{r_A^2}{r_B^2} = \left(\frac{2r_B}{r_B}ight)^2 = (2)^2 = 4$.Thus,$S_B = 4 S_A$.The stress on wire $B$ is four times the stress on wire $A$.

Two wires $A$ and $B$ are stretched by the same load. The radius of wire $A$ is double the radius of wire $B$. The stress on the wire $B$ as compared to the stress on the wire $A$ is

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