Two vibrating tuning forks produce progressiv | vedclass

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(C) The given wave equations are $Y_1 = 4 \sin(500 \pi t)$ and $Y_2 = 2 \sin(506 \pi t)$.Comparing these with the standard equation $Y = A \sin(\omega

Vedclass · Accepted Answer

$180$

Vedclass · Answer

(C) The given wave equations are $Y_1 = 4 \sin(500 \pi t)$ and $Y_2 = 2 \sin(506 \pi t)$.Comparing these with the standard equation $Y = A \sin(\omega t)$,where $\omega = 2 \pi 
u$:For the first wave: $\omega_1 = 500 \pi \implies 2 \pi 
u_1 = 500 \pi \implies 
u_1 = 250 	ext{ Hz}$.For the second wave: $\omega_2 = 506 \pi \implies 2 \pi 
u_2 = 506 \pi \implies 
u_2 = 253 	ext{ Hz}$.The beat frequency is the difference between the two frequencies: $
u_{beat} = |
u_2 - 
u_1| = |253 - 250| = 3 	ext{ beats/s}$.To find the number of beats per minute,multiply the beats per second by $60$: $3 	imes 60 = 180 	ext{ beats/min}$.

Two vibrating tuning forks produce progressive waves given by $Y_1 = 4 \sin(500 \pi t)$ and $Y_2 = 2 \sin(506 \pi t)$. The number of beats produced per minute is:

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