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(D) Let the two wires be placed in the $xy$-plane,parallel to the $y$-axis,at $x = -d/2$ and $x = d/2$. The currents are in opposite directions (e.g.,

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$0$

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(D) Let the two wires be placed in the $xy$-plane,parallel to the $y$-axis,at $x = -d/2$ and $x = d/2$. The currents are in opposite directions (e.g.,$+I$ in the $y$-direction and $-I$ in the $y$-direction). At the midpoint (origin),the magnetic field $B_1$ due to the first wire is directed into the plane ($-z$ direction),and the magnetic field $B_2$ due to the second wire is also directed into the plane ($-z$ direction). The resultant magnetic field $B = B_1 + B_2$ is perpendicular to the plane of the wires (along the $-z$ direction). The velocity $v$ of the charge $q$ is given as perpendicular to the plane of the wires (along the $z$ direction). The magnetic force on a moving charge is given by $F = q(v 	imes B)$. Since the velocity vector $v$ and the magnetic field vector $B$ are collinear (both along the $z$-axis),the cross product $v 	imes B = 0$. Therefore,the magnitude of the magnetic force acting on the charge is $0$.

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