Two unlike charges of magnitude q are separat | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The electric potential $V$ due to a point charge $Q$ at a distance $r$ is given by $V = \frac{1}{4\pi \varepsilon_0} \frac{Q}{r}$.Let the two char

Vedclass · Accepted Answer

Zero

Vedclass · Answer

(A) The electric potential $V$ due to a point charge $Q$ at a distance $r$ is given by $V = \frac{1}{4\pi \varepsilon_0} \frac{Q}{r}$.Let the two charges be $+q$ and $-q$,separated by a distance $2d$. The midpoint $O$ is at a distance $d$ from both charges.The potential at the midpoint $O$ is the algebraic sum of the potentials due to both charges:$V_O = V_{+q} + V_{-q}$$V_O = \frac{1}{4\pi \varepsilon_0} \frac{q}{d} + \frac{1}{4\pi \varepsilon_0} \frac{(-q)}{d}$$V_O = \frac{1}{4\pi \varepsilon_0} \left( \frac{q}{d} - \frac{q}{d} \right) = 0$Therefore,the potential at the midpoint is zero.

Two unlike charges of magnitude $q$ are separated by a distance $2d$. The potential at a point midway between them is

Similar Questions

Let $A, B$ and $C$ be the three points in a uniform electric field $(\overrightarrow{E})$ as shown. The electric potential is

The potential at a point,due to a positive charge of $100\,\mu C$ at a distance of $9\,m$,is

$A$ thin metallic disc is rotating with constant angular velocity about a vertical axis that is perpendicular to its plane and passes through its centre. The rotation causes the free electrons in the disc to redistribute. Assume that there is no external electric or magnetic field. Then,

The figure shows three circular arcs,each of radius $R$ and total charge as indicated. The net electric potential at the centre of curvature is

Two points $P$ and $Q$ are maintained at the potentials of $10 \ V$ and $-4 \ V$,respectively. The work done in moving $100$ electrons from $P$ to $Q$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module