A charge is spread non-uniformly on the surface of a hollow sphere of radius $R$, such that the charge density is given by $\sigma=\sigma_0(1-\sin \theta)$, where $\theta$ is the usual polar angle. The potential at the centre of the sphere is
$\frac{Q}{2 \pi \varepsilon_0 R}$
$\frac{Q}{\pi \varepsilon_0 R}$
$\frac{Q}{8 \pi \varepsilon_0 R}$
$\frac{Q}{4 \pi \varepsilon_0 R}$
At a certain distance from a point charge, the field intensity is $500\, Vm^{-1}$ and the potential is $-3000\, V$. The distance to the charge and the magnitude of the charge respectively are
Value of potential at a point due to a point charge is
The radius of nucleus of silver (atomic number $=$ $47$) is $3.4 \times {10^{ - 14}}\,m$. The electric potential on the surface of nucleus is $(e = 1.6 \times {10^{ - 19}}\,C)$
Calculate potential on the axis of a ring due to charge $Q$ uniformly distributed along the ring of radius $R$.
Write an equation for potential due to a system of charges