Two tuning forks P and Q are vibrated togethe | vedclass

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(C) From the graph,the slope of the line represents the beat frequency.For line $OA$,the number of beats in $1 \ s$ is $3$,so the beat frequency is $3

Vedclass · Accepted Answer

$344$

Vedclass · Answer

(C) From the graph,the slope of the line represents the beat frequency.For line $OA$,the number of beats in $1 \ s$ is $3$,so the beat frequency is $3 \ Hz$.For line $OB$,the number of beats in $1 \ s$ is $2$,so the beat frequency is $2 \ Hz$.Let $n_P = 341 \ Hz$ and $n_Q$ be the frequency of $Q$.Initially,$|n_P - n_Q| = 3 \ Hz$,which means $n_Q = 341 \pm 3$,so $n_Q = 344 \ Hz$ or $338 \ Hz$.When $Q$ is loaded with wax,its frequency $n_Q$ decreases.If $n_Q$ was $338 \ Hz$,loading it would decrease the frequency further away from $341 \ Hz$,increasing the beat frequency.If $n_Q$ was $344 \ Hz$,loading it would decrease the frequency towards $341 \ Hz$,decreasing the beat frequency.Since the graph shows the beat frequency decreases from $3 \ Hz$ to $2 \ Hz$,the frequency of $Q$ must be $344 \ Hz$.

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