Beats are produced by frequencies $v_1$ and $v_2$ $(v_1 > v_2)$. The duration of time between two successive minima is

Two sitar strings $A$ and $B$ playing the note $Sa$ are slightly out of tune and produce beats of frequency $5 \ Hz$. The tension of the string $B$ is slightly decreased and the beat frequency is found to decrease to $3 \ Hz$. What is the original frequency of $B$,if the frequency of $A$ is $255 \ Hz$?

When two tuning forks are sounded together,$6$ beats per second are heard. One of the forks is in unison with $0.70 \ m$ length of a sonometer wire and another fork is in unison with $0.69 \ m$ length of the same sonometer wire. The frequencies of the two tuning forks are:

Two tuning forks of frequencies $256 \ Hz$ and $258 \ Hz$ are sounded together. The time interval between two consecutive maxima is (in $s$)

Two tuning forks with frequencies $380 \,Hz$ and $384 \,Hz$ are sounded together. They produce $4$ beats per second. What is the time interval between the maximum sound and the next minimum sound?

If two tuning forks $A$ and $B$ are sounded together,they produce $4$ beats per second. $A$ is then slightly loaded with wax,and they produce $2$ beats when sounded again. The frequency of $A$ is $256 \ Hz$. The frequency of $B$ will be: (in $Hz$)