Two toys are sold at Rs. 504 each. One toy br | vedclass

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Question

(A) Let the cost price $(C.P.)$ of the first toy be $x$ and the second toy be $y$.For the first toy: $C.P. 	imes (1 + 12/100) = 504$$x 	imes (112/10

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$3 \frac{5}{13} \% 	ext{ Profit}$

Vedclass · Answer

(A) Let the cost price $(C.P.)$ of the first toy be $x$ and the second toy be $y$.For the first toy: $C.P. 	imes (1 + 12/100) = 504$$x 	imes (112/100) = 504$$x = (504 	imes 100) / 112 = 450$For the second toy: $C.P. 	imes (1 - 4/100) = 504$$y 	imes (96/100) = 504$$y = (504 	imes 100) / 96 = 525$Total $C.P. = 450 + 525 = 975$Total $S.P. = 504 + 504 = 1008$Since $S.P. > C.P.$,there is a profit.Profit $= 1008 - 975 = 33$Profit $\% = (33 / 975) 	imes 100 = (3300 / 975) = 44 / 13 = 3 \frac{5}{13} \%$

Two toys are sold at $Rs. 504$ each. One toy brings the dealer a gain of $12 \%$ and the other a loss of $4 \%$. The gain or loss percent by selling both the toys is

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