Two straight parallel wires, both carrying $10$ $ampere$ in the same direction attract each other with a force of $1 \times {10^{ - 3}}\,N$. If both currents are doubled, the force of attraction will be

A wire $X$ of length $50\; cm$ carrying a current of $2\,A$ is placed parallel to a long wire $Y$ of length $5\,m$. The wire $Y$ carries a current of $3\,A$. The distance between two wires is $5\,cm$ and currents flow in the same direction. The force acting on the wire $Y$ is.

Two long straight parallel wires, carrying (adjustable) current $I_1$ and $I_2$, are kept at a distance $d$ apart. If the force $'F'$ between the two wires is taken as 'positive' when the wires repel each other and 'negative' when the wires attract each other, the graph showing the dependence of $'F'$, on the product $I_1 I_2$, would be

A conducting wire bent in the form of a parabola $y^2 = 2x$ carries a current $i = 2 A$ as shown in figure. This wire is placed in a uniform magnetic field $\vec B =  - 4\,\hat k$ $Tesla$. The magnetic force on the wire is (in newton)

Two long current carrying thin wires, both with current $I$, are held by insulating threads oflength $L$ and are in equilibrium as shown in the figure, with threads making an angle '$\theta$' with the vertical. If wires have mass $\lambda$ per unit length then the value of $l$ is 
($g =$ gravitational acceleration)

For the circuit shown in figure, the direction and magnitude of the force on $PQR$ is :-